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X^2+60X-61=0
a = 1; b = 60; c = -61;
Δ = b2-4ac
Δ = 602-4·1·(-61)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3844}=62$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-62}{2*1}=\frac{-122}{2} =-61 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+62}{2*1}=\frac{2}{2} =1 $
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